Dik : m
aluminium= 500 gr T= 20⁰C
m
air= 117,5 gr
m
besi= 200 gr T=75⁰C
c
besi=0,448 cal/g⁰C
c
aluminium= 0,215 cal/g⁰C
Dit : T
akhir?
Jawab :
Qlepas = Qserap
(m.c.ΔT)besi = [(m.c)aluminium+(m.c)air] ΔT
200 gr . 0,448 cal/g⁰C . (75⁰C-Takhir =[(500
gr . 0,215 cal/g⁰C)+(117,5 gr . 1 cal/g⁰C)] (Takhir-20⁰C
89,6 cal/⁰C(75⁰C-Takhir) = [107,5 cal/⁰C +
117,5 cal/⁰C](Takhir-20⁰C)
6720 cal – 89,6 cal/⁰C Takhir = 224,5 cal/⁰C
(Takhir-20⁰C)
6720 cal – 89,6 cal/⁰C Takhir = 224,5 cal/⁰C
Takhir – 4490 cal
-89,6 cal/⁰C Takhir-224,5 cal/⁰C Takhir =
-4490 cal – 6720 cal
-314 cal/⁰C Takhir = -11210 cal
Takhir = 35,6⁰C
Dik : m
kalorimeter= 300 gr T=15⁰C
m
air= 500 gr
m
balok tembaga= 560 gr T= 100⁰C
Takhir=
22,5⁰C
Dit : c
tembaga?
Jawab :
Qlepas
= Qserap
(m.c.ΔT)baloktembaga
= [(m.c)kalorimeter+(m.c)air]ΔT
560
gr . c. (100⁰C-22,5⁰C)
= [(300 gr . c)+(500 gr . 1 cal/g⁰C)] (22,5⁰C-15⁰C)
560
gr . c. 77,5⁰C
= [300 gr . c + 500 cal/⁰C] 7,5⁰C
43400
gr⁰C
. c = 2250 gr⁰C . c +3750 cal
43400
gr⁰C
. c – 2250 gr⁰C . c = 3750 cal
41150
gr⁰C
. c = 3750 cal
c =
0,091 cal/gr⁰C
Dik : m
contoh= 50 gr T=100⁰C
m
air= 200 gr T= 20⁰C
m
kalorimeter=100 gr
Takhir=
22⁰C
c
tembaga= 0,092 cal/g⁰C
Dit : c
contoh?
Jawab :
Qlepas =
Qserap
(m.c.ΔT)contoh
= [(m.c)kalorimeter+(m.c)air]ΔT
50 gr . c
(100⁰C-22⁰C) = [(100 gr . 0,092 cal/g⁰C) + (200 gr . 1 cal/g⁰C)](22⁰C-20⁰C)
50 gr . c
. 78⁰C = [ 9,2 cal/⁰C + 200 cal/⁰C] 2⁰C
3900
gr⁰C
. c = 209,2 cal/⁰C . 2⁰C
3900 gr⁰C
. c = 418,4 cal
c = 0,107
cal/gr⁰C
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